Hacker News 100 @hn100@social.lansky.name
Public

Simpler Backoff

Link: commaok.xyz/post/simple-backof
Discussion: news.ycombinator.com/item?id=4

Simpler backoff

Exponential backoff with jitter is de rigeur for making service calls. This code, or something like it, probably looks really familiar: func do(ctx context.Context) error { const ( maxAttempts = 10 baseDelay = 1 * time.Second maxDelay = 60 * time.Second ) delay := baseDelay for attempt := range maxAttempts { err := request(ctx) if err == nil { return nil } delay *= 2 delay = min(delay, maxDelay) jitter := multiplyDuration(delay, rand.

commaok.xyz

0
0
0

If you have a fediverse account, you can quote this note from your own instance. Search https://social.lansky.name/users/hn100/statuses/114603432974363045 on your instance and quote it. (Note that quoting is not supported in Mastodon.)